
On the hydrolysis of esters according to the reaction: HCOO ... - Socratic
Nov 26, 2017 · HCOO^(-)(aq) + H_2O(l) rightleftharpoons HCOOH(aq) + OH^(-)(aq) If the solution is diluted, the reaction will shift left, because (i) water isn't in the equilibrium expression, and (ii) each …
Is it necessary to have oh group of phenol valways at ortho ... - Socratic
No, the "OH" group in phenol is by definition at "C1". > The structure of phenol is You can draw the structure like this: phenol2 However, the structure is not meta-phenol. It is phenol because the ring …
Question #477c5 - Socratic
On the product side the Carbonic Acid (#H_2CO_3#) is the Conjugate Acid as it is the hydrogen donor to the Conjugate Base (#OH^-#) as it receives the hydrogen ion.
Can you give the IUPAC name for the following (CH_3)_3C-OH
Aug 29, 2016 · So this is a propanol derivative: "2-methylpropan-2-ol" For "isopropyl alcohol", H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by -OH, so "propan-2 …
Question #2c594 - Socratic
The molar concentration of the ammonia is 0.015 mol/L. > Your textbook is misleading you. The 57.6 % figure is calculated as if the ammonia were in the form of "NH"_4"OH". Also, the correct value is 56.7 …
Question #bcb2d - Socratic
calculate moles of Acid, calculate moles of Base. subtract, #OH^-# should be in excess, calculate Molarity of #OH^-# , pOH = -log (#OH^-#), then 14-pOH = pH
Question #97503 - Socratic
Here's what I get. The general equation for the dissociation of a carboxylic acid is "R-COOH + H"_2"O" ⇌ "R-COO"^"-" + "H"_3"O"^+ All we have to do is write the ...
Question #74006 - Socratic
(d) is the correct option. CH_3CH(OH)CH_2CH_2CH_3 (pentan-2-ol) being secondary alcohol on oxidation first tansformed into ketone. CH_3CH(OH)CH_2CH_2CH_3stackrel([O])-> …
Question #a0f83 - Socratic
See the answer below... >- Problem no.1:- " "color (red) ("Butanoic acid" " " [has four carbons and contains -COOH group] Problem no.2:-" "color (red) ("Hexane-3,3-diol" " " [has 2 of -OH group in 3 …
Question #1a680 - Socratic
Jul 20, 2017 · Now, notice that the oxidation state of nitrogen goes from #color (blue) (+5)# on the reactants' side to #color (blue) (-3)# on the products' side, which basically means that every atom of …